380=x^2-x

Solution for 380=x^2-x equation:

380=x^2-x

We move all terms to the left:

380-(x^2-x)=0

We get rid of parentheses

-x^2+x+380=0

We add all the numbers together, and all the variables

-1x^2+x+380=0

a = -1; b = 1; c = +380;
Δ = b2-4ac
Δ = 12-4·(-1)·380
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1521}=39$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-39}{2*-1}=\frac{-40}{-2}
=+20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+39}{2*-1}=\frac{38}{-2}
=-19
$